4x(2)-52x+160=0

Solution for 4x(2)-52x+160=0 equation:

4x(2)-52x+160=0

We add all the numbers together, and all the variables

4x^2-52x+160=0

a = 4; b = -52; c = +160;
Δ = b2-4ac
Δ = -522-4·4·160
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-12}{2*4}=\frac{40}{8}
=5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+12}{2*4}=\frac{64}{8}
=8
$