4x(2x+1)=3(2x-5)

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Solution for 4x(2x+1)=3(2x-5) equation: 



4x(2x+1)=3(2x-5)

We move all terms to the left:

4x(2x+1)-(3(2x-5))=0

We multiply parentheses

8x^2+4x-(3(2x-5))=0



We calculate terms in parentheses: -(3(2x-5)), so:

3(2x-5)

We multiply parentheses

6x-15

Back to the equation:

-(6x-15)



We get rid of parentheses

8x^2+4x-6x+15=0

We add all the numbers together, and all the variables

8x^2-2x+15=0

a = 8; b = -2; c = +15;
Δ = b2-4ac
Δ = -22-4·8·15
Δ = -476
Delta is less than zero, so there is no solution for the equation

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