4x(2x-1)+x=2x-(2+x)-x

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Solution for 4x(2x-1)+x=2x-(2+x)-x equation:



4x(2x-1)+x=2x-(2+x)-x
We move all terms to the left:
4x(2x-1)+x-(2x-(2+x)-x)=0
We add all the numbers together, and all the variables
4x(2x-1)+x-(2x-(x+2)-x)=0
We add all the numbers together, and all the variables
x+4x(2x-1)-(2x-(x+2)-x)=0
We multiply parentheses
8x^2+x-4x-(2x-(x+2)-x)=0
We calculate terms in parentheses: -(2x-(x+2)-x), so:
2x-(x+2)-x
We add all the numbers together, and all the variables
x-(x+2)
We get rid of parentheses
x-x-2
We add all the numbers together, and all the variables
-2
Back to the equation:
-(-2)
We add all the numbers together, and all the variables
8x^2-3x+2=0
a = 8; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·8·2
Δ = -55
Delta is less than zero, so there is no solution for the equation

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