4x(2x-1)=-2(3x+16)

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Solution for 4x(2x-1)=-2(3x+16) equation: 



4x(2x-1)=-2(3x+16)

We move all terms to the left:

4x(2x-1)-(-2(3x+16))=0

We multiply parentheses

8x^2-4x-(-2(3x+16))=0



We calculate terms in parentheses: -(-2(3x+16)), so:

-2(3x+16)

We multiply parentheses

-6x-32

Back to the equation:

-(-6x-32)



We get rid of parentheses

8x^2-4x+6x+32=0

We add all the numbers together, and all the variables

8x^2+2x+32=0

a = 8; b = 2; c = +32;
Δ = b2-4ac
Δ = 22-4·8·32
Δ = -1020
Delta is less than zero, so there is no solution for the equation

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