4x(2x-10)=16

Solution for 4x(2x-10)=16 equation:

4x(2x-10)=16

We move all terms to the left:

4x(2x-10)-(16)=0

We multiply parentheses

8x^2-40x-16=0

a = 8; b = -40; c = -16;
Δ = b2-4ac
Δ = -402-4·8·(-16)
Δ = 2112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2112}=\sqrt{64*33}=\sqrt{64}*\sqrt{33}=8\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-8\sqrt{33}}{2*8}=\frac{40-8\sqrt{33}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+8\sqrt{33}}{2*8}=\frac{40+8\sqrt{33}}{16}
$