4x(3-1)=2x+12

Solution for 4x(3-1)=2x+12 equation:

4x(3-1)=2x+12

We move all terms to the left:

4x(3-1)-(2x+12)=0

We add all the numbers together, and all the variables

4x2-(2x+12)=0

We add all the numbers together, and all the variables

4x^2-(2x+12)=0

We get rid of parentheses

4x^2-2x-12=0

a = 4; b = -2; c = -12;
Δ = b2-4ac
Δ = -22-4·4·(-12)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-14}{2*4}=\frac{-12}{8}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+14}{2*4}=\frac{16}{8}
=2
$