If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x(3x+1)=+2
We move all terms to the left:
4x(3x+1)-(+2)=0
We add all the numbers together, and all the variables
4x(3x+1)-2=0
We multiply parentheses
12x^2+4x-2=0
a = 12; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·12·(-2)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{7}}{2*12}=\frac{-4-4\sqrt{7}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{7}}{2*12}=\frac{-4+4\sqrt{7}}{24} $
| -3=7p-65 | | 12x-34=5x+22 | | 5x-3/4=2x+3 | | 5d-2d=7 | | (x+3)/6=15 | | -28=-7p | | x(x)-x=0 | | `3x+5=2x+8 | | 16x^2-16x+2=0 | | 3+x/6=14 | | 5+x/7=26 | | 5+x/7=26 | | 6+x/3=18 | | m+9/3=11 | | 4y²=7y | | 6x-12=32+2x | | x5+3x4−9x3−31x2+36=0 | | k-13=12 | | y=(6.5+-2.5y)-3 | | -4,25x-7=10x-35,25 | | 7b-8b=5b-3+b+4 | | 5y^2-7=19 | | 2y-3=5y-39 | | 4(2e-5)=48 | | 4a-2=33-a | | 4d-7=5-2d | | 5(5-x)=40 | | (2x+5)+(3x−6)=14 | | M4+2m+1=0 | | -25=4x+15. | | -25=4x+15.×= | | 0,4x=7√0,4 |