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4x(3x+2)-340=0
We multiply parentheses
12x^2+8x-340=0
a = 12; b = 8; c = -340;
Δ = b2-4ac
Δ = 82-4·12·(-340)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16384}=128$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-128}{2*12}=\frac{-136}{24} =-5+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+128}{2*12}=\frac{120}{24} =5 $
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