4x(3x+5)=0

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Solution for 4x(3x+5)=0 equation:



4x(3x+5)=0
We multiply parentheses
12x^2+20x=0
a = 12; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·12·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*12}=\frac{-40}{24} =-1+2/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*12}=\frac{0}{24} =0 $

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