4x(3x+6)=96

Solution for 4x(3x+6)=96 equation:

4x(3x+6)=96

We move all terms to the left:

4x(3x+6)-(96)=0

We multiply parentheses

12x^2+24x-96=0

a = 12; b = 24; c = -96;
Δ = b2-4ac
Δ = 242-4·12·(-96)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-72}{2*12}=\frac{-96}{24}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+72}{2*12}=\frac{48}{24}
=2
$