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4x(3x-1)=5x
We move all terms to the left:
4x(3x-1)-(5x)=0
We add all the numbers together, and all the variables
-5x+4x(3x-1)=0
We multiply parentheses
12x^2-5x-4x=0
We add all the numbers together, and all the variables
12x^2-9x=0
a = 12; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·12·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*12}=\frac{18}{24} =3/4 $
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