4x(4-2)=24-4x

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Solution for 4x(4-2)=24-4x equation:



4x(4-2)=24-4x
We move all terms to the left:
4x(4-2)-(24-4x)=0
We add all the numbers together, and all the variables
4x2-(-4x+24)=0
We add all the numbers together, and all the variables
4x^2-(-4x+24)=0
We get rid of parentheses
4x^2+4x-24=0
a = 4; b = 4; c = -24;
Δ = b2-4ac
Δ = 42-4·4·(-24)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-20}{2*4}=\frac{-24}{8} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+20}{2*4}=\frac{16}{8} =2 $

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