4x(40/4x)+(4x)(2)=(4x)(40/x)

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Solution for 4x(40/4x)+(4x)(2)=(4x)(40/x) equation: 



4x(40/4x)+(4x)(2)=(4x)(40/x)

We move all terms to the left:

4x(40/4x)+(4x)(2)-((4x)(40/x))=0



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4x(+40/4x)+4x2-(4x(+40/x))=0

We add all the numbers together, and all the variables

4x^2+4x(+40/4x)-(4x(+40/x))=0

We multiply parentheses

4x^2+160x^2-(4x(+40/x))=0

We multiply all the terms by the denominator


4x^2*x))+160x^2*x))-(4x(+40=0

Wy multiply elements

4x^4=0

We do not support expression: x^4

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