4x(43-6x)=98x-42x

Solution for 4x(43-6x)=98x-42x equation:

4x(43-6x)=98x-42x

We move all terms to the left:

4x(43-6x)-(98x-42x)=0

We add all the numbers together, and all the variables

4x(-6x+43)-(+56x)=0

We multiply parentheses

-24x^2+172x-(+56x)=0

We get rid of parentheses

-24x^2+172x-56x=0

We add all the numbers together, and all the variables

-24x^2+116x=0

a = -24; b = 116; c = 0;
Δ = b2-4ac
Δ = 1162-4·(-24)·0
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13456}=116$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(116)-116}{2*-24}=\frac{-232}{-48}
=4+5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(116)+116}{2*-24}=\frac{0}{-48}
=0
$