4x(4x-2)+2=16x-7

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Solution for 4x(4x-2)+2=16x-7 equation: 



4x(4x-2)+2=16x-7

We move all terms to the left:

4x(4x-2)+2-(16x-7)=0

We multiply parentheses

16x^2-8x-(16x-7)+2=0

We get rid of parentheses

16x^2-8x-16x+7+2=0

We add all the numbers together, and all the variables

16x^2-24x+9=0

a = 16; b = -24; c = +9;
Δ = b2-4ac
Δ = -242-4·16·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{24}{32}=3/4$

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