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4x(6-x)=24
We move all terms to the left:
4x(6-x)-(24)=0
We add all the numbers together, and all the variables
4x(-1x+6)-24=0
We multiply parentheses
-4x^2+24x-24=0
a = -4; b = 24; c = -24;
Δ = b2-4ac
Δ = 242-4·(-4)·(-24)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8\sqrt{3}}{2*-4}=\frac{-24-8\sqrt{3}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8\sqrt{3}}{2*-4}=\frac{-24+8\sqrt{3}}{-8} $
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