4x(6x+2)-2(6+x)-20=12(1+2

Solution for 4x(6x+2)-2(6+x)-20=12(1+2 equation:

4x(6x+2)-2(6+x)-20=12(1+2

We move all terms to the left:

4x(6x+2)-2(6+x)-20-(12(1+2)=0

We add all the numbers together, and all the variables

4x(6x+2)-2(x+6)-20-(123=0

We add all the numbers together, and all the variables

4x(6x+2)-2(x+6)=0

We multiply parentheses

24x^2+8x-2x-12=0

We add all the numbers together, and all the variables

24x^2+6x-12=0

a = 24; b = 6; c = -12;
Δ = b2-4ac
Δ = 62-4·24·(-12)
Δ = 1188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1188}=\sqrt{36*33}=\sqrt{36}*\sqrt{33}=6\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{33}}{2*24}=\frac{-6-6\sqrt{33}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{33}}{2*24}=\frac{-6+6\sqrt{33}}{48}
$