4x(6x+2)-2(6+x)-20=12x(1+2x)-2x

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Solution for 4x(6x+2)-2(6+x)-20=12x(1+2x)-2x equation: 



4x(6x+2)-2(6+x)-20=12x(1+2x)-2x

We move all terms to the left:

4x(6x+2)-2(6+x)-20-(12x(1+2x)-2x)=0

We add all the numbers together, and all the variables

4x(6x+2)-2(x+6)-(12x(2x+1)-2x)-20=0

We multiply parentheses

24x^2+8x-2x-(12x(2x+1)-2x)-12-20=0



We calculate terms in parentheses: -(12x(2x+1)-2x), so:

12x(2x+1)-2x

We add all the numbers together, and all the variables

-2x+12x(2x+1)

We multiply parentheses

24x^2-2x+12x

We add all the numbers together, and all the variables

24x^2+10x

Back to the equation:

-(24x^2+10x)



We add all the numbers together, and all the variables

24x^2+6x-(24x^2+10x)-32=0

We get rid of parentheses

24x^2-24x^2+6x-10x-32=0

We add all the numbers together, and all the variables

-4x-32=0

We move all terms containing x to the left, all other terms to the right

-4x=32

x=32/-4

x=-8

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