If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x(6x-3)=92
We move all terms to the left:
4x(6x-3)-(92)=0
We multiply parentheses
24x^2-12x-92=0
a = 24; b = -12; c = -92;
Δ = b2-4ac
Δ = -122-4·24·(-92)
Δ = 8976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8976}=\sqrt{16*561}=\sqrt{16}*\sqrt{561}=4\sqrt{561}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{561}}{2*24}=\frac{12-4\sqrt{561}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{561}}{2*24}=\frac{12+4\sqrt{561}}{48} $
| x/3+8.50=13.25 | | 4x(6x-3=92 | | 5+7r=-2+6r | | 13=3f−5 | | 3(5+3x)=96 | | 15−3j=6 | | 0.06x-0.09=0.05x+0.12-0.15 | | 7r+16=3r$24 | | -109=-7(-2v+7)+v | | w/6=-19.2 | | 4=10−3k | | -3x+x+4=-2x | | j4− 3=1 | | N+3.4-0.5n=-0.25 | | z+57=-3 | | 19+4.50h=9+5.75h | | Q/3(12f-3)=4f-1 | | -(3-g)=7g+3 | | 11+-9p=9p | | 2n+2(n+.6)=2n+2(n+.1) | | 8y-8(y-1)=6-(16y-4)-10 | | 2s+13=2s | | 14w-5=7w+2 | | -2x-3(-8+6x)=4(-5-4x) | | 9v+14=6+2 | | 0.4(0.3x+1)=1.2x+1 | | 13=x=6 | | (3x+4-x)=16 | | 7m^2-m+3=0 | | -7r=70 | | 7=x÷2 | | 5a-8=2a+18 |