4x(7+3x)=28x+12x2

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Solution for 4x(7+3x)=28x+12x2 equation: 



4x(7+3x)=28x+12x^2

We move all terms to the left:

4x(7+3x)-(28x+12x^2)=0

We add all the numbers together, and all the variables

-(28x+12x^2)+4x(3x+7)=0

We multiply parentheses

-(28x+12x^2)+12x^2+28x=0

We get rid of parentheses

-12x^2+12x^2-28x+28x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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