4x(7x+20)-60x=18

Solution for 4x(7x+20)-60x=18 equation:

4x(7x+20)-60x=18

We move all terms to the left:

4x(7x+20)-60x-(18)=0

We add all the numbers together, and all the variables

-60x+4x(7x+20)-18=0

We multiply parentheses

28x^2-60x+80x-18=0

We add all the numbers together, and all the variables

28x^2+20x-18=0

a = 28; b = 20; c = -18;
Δ = b2-4ac
Δ = 202-4·28·(-18)
Δ = 2416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2416}=\sqrt{16*151}=\sqrt{16}*\sqrt{151}=4\sqrt{151}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{151}}{2*28}=\frac{-20-4\sqrt{151}}{56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{151}}{2*28}=\frac{-20+4\sqrt{151}}{56}
$