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4x(9x+25)=90
We move all terms to the left:
4x(9x+25)-(90)=0
We multiply parentheses
36x^2+100x-90=0
a = 36; b = 100; c = -90;
Δ = b2-4ac
Δ = 1002-4·36·(-90)
Δ = 22960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{22960}=\sqrt{16*1435}=\sqrt{16}*\sqrt{1435}=4\sqrt{1435}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{1435}}{2*36}=\frac{-100-4\sqrt{1435}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{1435}}{2*36}=\frac{-100+4\sqrt{1435}}{72} $
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