4x(x)=(x+6)(2x+40)

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Solution for 4x(x)=(x+6)(2x+40) equation: 



4x(x)=(x+6)(2x+40)

We move all terms to the left:

4x(x)-((x+6)(2x+40))=0

We multiply parentheses ..

-((+2x^2+40x+12x+240))+4xx=0



We calculate terms in parentheses: -((+2x^2+40x+12x+240)), so:

(+2x^2+40x+12x+240)

We get rid of parentheses

2x^2+40x+12x+240

We add all the numbers together, and all the variables

2x^2+52x+240

Back to the equation:

-(2x^2+52x+240)



We get rid of parentheses

-2x^2-52x+4xx-240=0

We move all terms containing x to the left, all other terms to the right

-2x^2-52x+4xx=240

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