4x(x+-3)=-40

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Solution for 4x(x+-3)=-40 equation: 



4x(x+-3)=-40

We move all terms to the left:

4x(x+-3)-(-40)=0

We add all the numbers together, and all the variables

4x(x-3)-(-40)=0

We add all the numbers together, and all the variables

4x(x-3)+40=0

We multiply parentheses

4x^2-12x+40=0

a = 4; b = -12; c = +40;
Δ = b2-4ac
Δ = -122-4·4·40
Δ = -496
Delta is less than zero, so there is no solution for the equation

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