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4x(x+1)=-2(x-26)
We move all terms to the left:
4x(x+1)-(-2(x-26))=0
We multiply parentheses
4x^2+4x-(-2(x-26))=0
We calculate terms in parentheses: -(-2(x-26)), so:We get rid of parentheses
-2(x-26)
We multiply parentheses
-2x+52
Back to the equation:
-(-2x+52)
4x^2+4x+2x-52=0
We add all the numbers together, and all the variables
4x^2+6x-52=0
a = 4; b = 6; c = -52;
Δ = b2-4ac
Δ = 62-4·4·(-52)
Δ = 868
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{868}=\sqrt{4*217}=\sqrt{4}*\sqrt{217}=2\sqrt{217}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{217}}{2*4}=\frac{-6-2\sqrt{217}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{217}}{2*4}=\frac{-6+2\sqrt{217}}{8} $
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