4x(x+11)=131

Solution for 4x(x+11)=131 equation:

4x(x+11)=131

We move all terms to the left:

4x(x+11)-(131)=0

We multiply parentheses

4x^2+44x-131=0

a = 4; b = 44; c = -131;
Δ = b2-4ac
Δ = 442-4·4·(-131)
Δ = 4032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4032}=\sqrt{576*7}=\sqrt{576}*\sqrt{7}=24\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-24\sqrt{7}}{2*4}=\frac{-44-24\sqrt{7}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+24\sqrt{7}}{2*4}=\frac{-44+24\sqrt{7}}{8}
$