4x(x+12)-5=79

Solution for 4x(x+12)-5=79 equation:

4x(x+12)-5=79

We move all terms to the left:

4x(x+12)-5-(79)=0

We add all the numbers together, and all the variables

4x(x+12)-84=0

We multiply parentheses

4x^2+48x-84=0

a = 4; b = 48; c = -84;
Δ = b2-4ac
Δ = 482-4·4·(-84)
Δ = 3648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3648}=\sqrt{64*57}=\sqrt{64}*\sqrt{57}=8\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-8\sqrt{57}}{2*4}=\frac{-48-8\sqrt{57}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+8\sqrt{57}}{2*4}=\frac{-48+8\sqrt{57}}{8}
$