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4x(x+14)=88
We move all terms to the left:
4x(x+14)-(88)=0
We multiply parentheses
4x^2+56x-88=0
a = 4; b = 56; c = -88;
Δ = b2-4ac
Δ = 562-4·4·(-88)
Δ = 4544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4544}=\sqrt{64*71}=\sqrt{64}*\sqrt{71}=8\sqrt{71}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-8\sqrt{71}}{2*4}=\frac{-56-8\sqrt{71}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+8\sqrt{71}}{2*4}=\frac{-56+8\sqrt{71}}{8} $
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