4x(x+2)=3x(x+1)

Solution for 4x(x+2)=3x(x+1) equation:

4x(x+2)=3x(x+1)

We move all terms to the left:

4x(x+2)-(3x(x+1))=0

We multiply parentheses

4x^2+8x-(3x(x+1))=0


We calculate terms in parentheses: -(3x(x+1)), so:

3x(x+1)

We multiply parentheses

3x^2+3x

Back to the equation:

-(3x^2+3x)


We get rid of parentheses

4x^2-3x^2+8x-3x=0

We add all the numbers together, and all the variables

x^2+5x=0

a = 1; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·1·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*1}=\frac{0}{2}
=0
$