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4x(x+3)-3x(3x+9)=11x-16x-15
We move all terms to the left:
4x(x+3)-3x(3x+9)-(11x-16x-15)=0
We add all the numbers together, and all the variables
4x(x+3)-3x(3x+9)-(-5x-15)=0
We multiply parentheses
4x^2-9x^2+12x-27x-(-5x-15)=0
We get rid of parentheses
4x^2-9x^2+12x-27x+5x+15=0
We add all the numbers together, and all the variables
-5x^2-10x+15=0
a = -5; b = -10; c = +15;
Δ = b2-4ac
Δ = -102-4·(-5)·15
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-20}{2*-5}=\frac{-10}{-10} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+20}{2*-5}=\frac{30}{-10} =-3 $
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