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4x(x+3)=55
We move all terms to the left:
4x(x+3)-(55)=0
We multiply parentheses
4x^2+12x-55=0
a = 4; b = 12; c = -55;
Δ = b2-4ac
Δ = 122-4·4·(-55)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-32}{2*4}=\frac{-44}{8} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+32}{2*4}=\frac{20}{8} =2+1/2 $
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