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4x(x+4)=-15
We move all terms to the left:
4x(x+4)-(-15)=0
We add all the numbers together, and all the variables
4x(x+4)+15=0
We multiply parentheses
4x^2+16x+15=0
a = 4; b = 16; c = +15;
Δ = b2-4ac
Δ = 162-4·4·15
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{16}=4x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*4}=\frac{-20}{8} =-2+1/2x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*4}=\frac{-12}{8} =-1+1/2
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