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4x(x+5)=2x-35
We move all terms to the left:
4x(x+5)-(2x-35)=0
We multiply parentheses
4x^2+20x-(2x-35)=0
We get rid of parentheses
4x^2+20x-2x+35=0
We add all the numbers together, and all the variables
4x^2+18x+35=0
a = 4; b = 18; c = +35;
Δ = b2-4ac
Δ = 182-4·4·35
Δ = -236
Delta is less than zero, so there is no solution for the equation
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