4x(x+5)=4x(x+3)+8

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Solution for 4x(x+5)=4x(x+3)+8 equation: 



4x(x+5)=4x(x+3)+8

We move all terms to the left:

4x(x+5)-(4x(x+3)+8)=0

We multiply parentheses

4x^2+20x-(4x(x+3)+8)=0



We calculate terms in parentheses: -(4x(x+3)+8), so:

4x(x+3)+8

We multiply parentheses

4x^2+12x+8

Back to the equation:

-(4x^2+12x+8)



We get rid of parentheses

4x^2-4x^2+20x-12x-8=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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