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4x(x+6)=149
We move all terms to the left:
4x(x+6)-(149)=0
We multiply parentheses
4x^2+24x-149=0
a = 4; b = 24; c = -149;
Δ = b2-4ac
Δ = 242-4·4·(-149)
Δ = 2960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2960}=\sqrt{16*185}=\sqrt{16}*\sqrt{185}=4\sqrt{185}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{185}}{2*4}=\frac{-24-4\sqrt{185}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{185}}{2*4}=\frac{-24+4\sqrt{185}}{8} $
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