4x(x+650)=1850

Solution for 4x(x+650)=1850 equation:

4x(x+650)=1850

We move all terms to the left:

4x(x+650)-(1850)=0

We multiply parentheses

4x^2+2600x-1850=0

a = 4; b = 2600; c = -1850;
Δ = b2-4ac
Δ = 26002-4·4·(-1850)
Δ = 6789600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6789600}=\sqrt{3600*1886}=\sqrt{3600}*\sqrt{1886}=60\sqrt{1886}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2600)-60\sqrt{1886}}{2*4}=\frac{-2600-60\sqrt{1886}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2600)+60\sqrt{1886}}{2*4}=\frac{-2600+60\sqrt{1886}}{8}
$