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4x(x+7)=32
We move all terms to the left:
4x(x+7)-(32)=0
We multiply parentheses
4x^2+28x-32=0
a = 4; b = 28; c = -32;
Δ = b2-4ac
Δ = 282-4·4·(-32)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-36}{2*4}=\frac{-64}{8} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+36}{2*4}=\frac{8}{8} =1 $
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