4x(x+8)=7x+10

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Solution for 4x(x+8)=7x+10 equation:



4x(x+8)=7x+10
We move all terms to the left:
4x(x+8)-(7x+10)=0
We multiply parentheses
4x^2+32x-(7x+10)=0
We get rid of parentheses
4x^2+32x-7x-10=0
We add all the numbers together, and all the variables
4x^2+25x-10=0
a = 4; b = 25; c = -10;
Δ = b2-4ac
Δ = 252-4·4·(-10)
Δ = 785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{785}}{2*4}=\frac{-25-\sqrt{785}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{785}}{2*4}=\frac{-25+\sqrt{785}}{8} $

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