4x(x-1)=(2x+1)(2x-2)

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Solution for 4x(x-1)=(2x+1)(2x-2) equation:



4x(x-1)=(2x+1)(2x-2)
We move all terms to the left:
4x(x-1)-((2x+1)(2x-2))=0
We multiply parentheses
4x^2-4x-((2x+1)(2x-2))=0
We multiply parentheses ..
4x^2-((+4x^2-4x+2x-2))-4x=0
We calculate terms in parentheses: -((+4x^2-4x+2x-2)), so:
(+4x^2-4x+2x-2)
We get rid of parentheses
4x^2-4x+2x-2
We add all the numbers together, and all the variables
4x^2-2x-2
Back to the equation:
-(4x^2-2x-2)
We add all the numbers together, and all the variables
4x^2-4x-(4x^2-2x-2)=0
We get rid of parentheses
4x^2-4x^2-4x+2x+2=0
We add all the numbers together, and all the variables
-2x+2=0
We move all terms containing x to the left, all other terms to the right
-2x=-2
x=-2/-2
x=1

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