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4x(x-10)=-84
We move all terms to the left:
4x(x-10)-(-84)=0
We add all the numbers together, and all the variables
4x(x-10)+84=0
We multiply parentheses
4x^2-40x+84=0
a = 4; b = -40; c = +84;
Δ = b2-4ac
Δ = -402-4·4·84
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-16}{2*4}=\frac{24}{8} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+16}{2*4}=\frac{56}{8} =7 $
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