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4x(x-2)=3(1.5+x)
We move all terms to the left:
4x(x-2)-(3(1.5+x))=0
We add all the numbers together, and all the variables
4x(x-2)-(3(x+1.5))=0
We multiply parentheses
4x^2-8x-(3(x+1.5))=0
We calculate terms in parentheses: -(3(x+1.5)), so:We get rid of parentheses
3(x+1.5)
We multiply parentheses
3x+4.5
Back to the equation:
-(3x+4.5)
4x^2-8x-3x-4.5=0
We add all the numbers together, and all the variables
4x^2-11x-4.5=0
a = 4; b = -11; c = -4.5;
Δ = b2-4ac
Δ = -112-4·4·(-4.5)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{193}}{2*4}=\frac{11-\sqrt{193}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{193}}{2*4}=\frac{11+\sqrt{193}}{8} $
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