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4x(x-3)=-4x-6
We move all terms to the left:
4x(x-3)-(-4x-6)=0
We multiply parentheses
4x^2-12x-(-4x-6)=0
We get rid of parentheses
4x^2-12x+4x+6=0
We add all the numbers together, and all the variables
4x^2-8x+6=0
a = 4; b = -8; c = +6;
Δ = b2-4ac
Δ = -82-4·4·6
Δ = -32
Delta is less than zero, so there is no solution for the equation
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