If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x(x-3)=12
We move all terms to the left:
4x(x-3)-(12)=0
We multiply parentheses
4x^2-12x-12=0
a = 4; b = -12; c = -12;
Δ = b2-4ac
Δ = -122-4·4·(-12)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{21}}{2*4}=\frac{12-4\sqrt{21}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{21}}{2*4}=\frac{12+4\sqrt{21}}{8} $
| 3x=57/3 | | 7d^2=-12 | | x=7+2(-4) | | -4n-2=17 | | -2r+7=-41 | | x+7^4=10 | | -9.5*6^10x=-22 | | 5(7+2y)-6y=19 | | x=-10+6/11 | | 19x+4+110=8x-2 | | -n+-17n+-18n−n+20n=-17 | | 5^(x+2)=3125 | | (1/25)^(-1/2)=10x | | 5x=6=41 | | 2x+2-10=18 | | 2x+6+7=9 | | (4^6x)=1 | | 4r-6=r+12 | | x/30=0.01 | | -29-19x=-13-20x | | 3/4=x+1/10 | | 13x+6+8+3x=70 | | 3h+11=5 | | 3x-6=-2+4,x | | 8x+1=-37+10x | | 3r-10=2(r+6) | | 7/16+x=11/16 | | -9x-x+8x=-23 | | 2m=9m/3-4 | | -19+-18x=16x+17 | | 8+x/8=5 | | 4(x+11)-x=8 |