4x(x-3)=4x-12

Solution for 4x(x-3)=4x-12 equation:

4x(x-3)=4x-12

We move all terms to the left:

4x(x-3)-(4x-12)=0

We multiply parentheses

4x^2-12x-(4x-12)=0

We get rid of parentheses

4x^2-12x-4x+12=0

We add all the numbers together, and all the variables

4x^2-16x+12=0

a = 4; b = -16; c = +12;
Δ = b2-4ac
Δ = -162-4·4·12
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8}{2*4}=\frac{24}{8}
=3
$