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4x(x-6)=16
We move all terms to the left:
4x(x-6)-(16)=0
We multiply parentheses
4x^2-24x-16=0
a = 4; b = -24; c = -16;
Δ = b2-4ac
Δ = -242-4·4·(-16)
Δ = 832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{832}=\sqrt{64*13}=\sqrt{64}*\sqrt{13}=8\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8\sqrt{13}}{2*4}=\frac{24-8\sqrt{13}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8\sqrt{13}}{2*4}=\frac{24+8\sqrt{13}}{8} $
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