4x)=(3x-2)(3x-2)-(9x-5)(x+1)

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Solution for 4x)=(3x-2)(3x-2)-(9x-5)(x+1) equation: 



4x)=(3x-2)(3x-2)-(9x-5)(x+1)

We move all terms to the left:

4x)-((3x-2)(3x-2)-(9x-5)(x+1))=0

We multiply parentheses ..

4x)-((+9x^2-6x-6x+4)-(9x-5)(x+1))=0

We multiply parentheses ..

4x)-((+9x^2-6x-6x+4)-(+9x^2+9x-5x-5))=0

We get rid of parentheses

4x)-((+9x^2-6x-6x+4)-9x^2-9x+5x+5)=0

We add all the numbers together, and all the variables

-9x^2+4x)-((+9x^2-6x-6x+4)-4x=0

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