4x*12x=320

Solution for 4x*12x=320 equation:

4x*12x=320

We move all terms to the left:

4x*12x-(320)=0

Wy multiply elements

48x^2-320=0

a = 48; b = 0; c = -320;
Δ = b2-4ac
Δ = 02-4·48·(-320)
Δ = 61440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{61440}=\sqrt{4096*15}=\sqrt{4096}*\sqrt{15}=64\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{15}}{2*48}=\frac{0-64\sqrt{15}}{96}
=-\frac{64\sqrt{15}}{96}
=-\frac{2\sqrt{15}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{15}}{2*48}=\frac{0+64\sqrt{15}}{96}
=\frac{64\sqrt{15}}{96}
=\frac{2\sqrt{15}}{3}
$