4x*3x=104

Solution for 4x*3x=104 equation:

4x*3x=104

We move all terms to the left:

4x*3x-(104)=0

Wy multiply elements

12x^2-104=0

a = 12; b = 0; c = -104;
Δ = b2-4ac
Δ = 02-4·12·(-104)
Δ = 4992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4992}=\sqrt{64*78}=\sqrt{64}*\sqrt{78}=8\sqrt{78}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{78}}{2*12}=\frac{0-8\sqrt{78}}{24}
=-\frac{8\sqrt{78}}{24}
=-\frac{\sqrt{78}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{78}}{2*12}=\frac{0+8\sqrt{78}}{24}
=\frac{8\sqrt{78}}{24}
=\frac{\sqrt{78}}{3}
$