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4x*3x=588
We move all terms to the left:
4x*3x-(588)=0
Wy multiply elements
12x^2-588=0
a = 12; b = 0; c = -588;
Δ = b2-4ac
Δ = 02-4·12·(-588)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28224}=168$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-168}{2*12}=\frac{-168}{24} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+168}{2*12}=\frac{168}{24} =7 $
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