4x*4x-13x+19=3x+4

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Solution for 4x*4x-13x+19=3x+4 equation: 



4x*4x-13x+19=3x+4

We move all terms to the left:

4x*4x-13x+19-(3x+4)=0

We add all the numbers together, and all the variables

-13x+4x*4x-(3x+4)+19=0

Wy multiply elements

16x^2-13x-(3x+4)+19=0

We get rid of parentheses

16x^2-13x-3x-4+19=0

We add all the numbers together, and all the variables

16x^2-16x+15=0

a = 16; b = -16; c = +15;
Δ = b2-4ac
Δ = -162-4·16·15
Δ = -704
Delta is less than zero, so there is no solution for the equation

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